For positive integers $n$ and $d$, $n \div d$ is an integer only if $n$ is divisible by $d$, but if it is not divisible, a non-zero number appears after the decimal point. In such a case, an integer can be obtained by rounding up or truncating the decimal point.
On the other hand, there is a way to use truncation to find the integer rounded up to the nearest integer in $n \div d$. By rounding down the decimal point of $(n + d - 1) \div d$, we can find the integer rounded up to the nearest integer in $n \div d$.
Given a positive integer $n$ and $d$, create a program to find the integer obtained by rounding up the decimal point of $n \div d$.
The input is given in the following format.
$n$ $d$
A positive integer $n$ ($1 \leq n \leq ≤ 1$00) and $d$ ($1 \leq d \leq 100$) are given in the first line.
Output the integer obtained by rounding up the decimal point of $n \div d$ to one line. Do not output decimals or numbers less than or equal to the decimal point.
2 3
1
5 3
2
6 3
2